Q.8. A person running at speed 3 m/s w.r.t. ground on a ship perpendicular to the direction of motion of the ship moving at 4 m/s, throws a ball vertically up at 5 m/s. Horizontal range of the ball w.r.t. ground is
(1) 20 m
(2) 15 m
(3) 10 m
(4) 5 m

Dear student,Ux=32+42=5m/sTiem taken by ball=2usinθgθ=90oT=2×5×110=1sHorizontal range=Ux×T=5×1=5mRegards

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