Dear Student, Given, v=kt We know that,v=Rate of change of displacementv=dxdt=ktor dx=kt dtOn integration,∫dx=∫kt dtor x=kt22Therefore, distance covered in 3 seconds will be,x=2×322=9 m Regards

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Dear Student,
Given,
v=kt

We know that, v = Rate of change of displacement v = \frac{dx}{dt} = kt or dx = kt . dt On integration, \int dx = \int kt dt or x = k \frac{t^{2}}{2} Therefore, distance covered in 3 seconds will be, x = 2 \times \frac{3^{2}}{2} = 9 m

Regards

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