The 200 N force is to be resolved into components along the lines a-a' and b-b'.
(a) Determine the angle P by trigonometry knowing that the component along a-a' is 150 N.
(b) What is the corresponding value of the component along b-b'?
answer: (a) 103.0 degrees (b) 276 N
Please help me with the solution.
Dear student, the image in your question is still not visible. Please post the question with the necessary image so that we can answer your query.