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THE DIAGONALS OF A PARALLELOGRAM ARE REPRESENTED BY VECTORS P=5i-4j+3k and q=3i+2j-k.

THE AREA OF THE PARALLELOGRAM IS?

The area  of a parallelogram with diagonal p→ and q → is 12|p→ ×q→|We have,p→=5 i^-4j^+3k^q→=3 i^+2 j^- k^ Now,p→×q→=(5 i^-4j^+3k^) × (3 i^+2 j^- k^)Using cross product,p→×q→=-2i^ +14j^+22k^|p→×q→|=(-2)2+142+222=4+196+484=26.15Area=26.15/2=13.075 sq unit

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