two paper screens A and B Are seperated by a distance of 100m. A gullet penetrates A and B at points P AND Q respectively. Where Q is 10 cm below P. If bullet is travelling horizontally at the time of hitting A the velocity of bullet ar A is nearly how much?Help experts

Let, x=100 m and h=10cm
Using equation of motion we can calculate the time of the motion as,
 h=ut+12gt2
Assuming initial velocity to be zero and g=10 m/s2, we get,
 t=2hgt=2×10 cm10 m/s2t=2×0.1 m10 m/s2t=0.14 s
Now, again using equation of motion as,
 x=vtor,v=xt
we get,
v=100 m0.14 sv=707.11 m/s

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