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Syllabus

1.Find the missing frequency f, if the mode of the given data is 154.

Classes

120-130

130-140

140-150

150-160

160-170

170-180

Frequency

2

8

12

f

9

7

plzz give an answer fast....

10. If median = 15 and mean = 16, find mode of the distributionwhat is hit and trial method .

In the step deviation method,

What is the meaning of

u_{i }?If the median of the distribution is given below is 28.5, find the values of

xandy.Class intervalFrequency0 − 10

5

10 − 20

x20 − 30

20

30 − 40

15

40 − 50

y50 − 60

5

Total

60

Q. 27. School held sports day in which 150 students participated. Age of students are given in the following frequency distribution;

(in years)

For the above data, draw a more than type, ogive and from the curve, find median. Verify it by actual calculations.

if the median of the following frequency distribution is 24. find the missing frequency x :

Age Number of persons

0 - 10 5

10 - 20 25

20 - 30 x

30 - 40 18

40 - 50 7

In statistics Ex 14.1 Q8 of class 10..

if we solve the question by using step deviation, what value of h will

we take as in the book it is written that if the class sizes are

unequal, and xi are large numerically we can still apply step

deviation method taking h to be a suitable divisor of all the di "

But in Example 3 of statistics we have taken h to be 20 whereas it is

not a divisor to all the di's. It is not a divisor to -75...

Please explain this to me

find the missing frequencies if N=100 and median is 32.

marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total

no. of students-10 ,? ,25 ,30 ,? ,10 ,100.

monthly consumption of electricity of some consumers is given below as a distribution. Find the missing frequency(x), if mode is given to be 200 units.

Monthly cosumption(in units ) 90-120 120-150 150-180 180-210 210-240

Number of consumers 20 15 X 75 30

The median of the following distribution is 30. Find the missing frequencies f1 and f2:

Class frequency

0-10 10

10-20 10

20-30 f1

30-40 30

40-50 f2

50-60 10

Total 100

how to calculate mode if two classes have same and highest frequency (bimodal) ?

the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?

IF THE N/2 IS EQUAL TO THE CUMULATIVE FREQUENCY THEN WE WOULD REGARD THAT CLASS AS THE MEDIAN CLASS OR NOT.

how to find the mean if the class intervals are unequal??

like fr e- 0-10,10-30,30-35....

The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______

The following table shows the distribution of some families according to expenditure per week .the number of families for two class intervalsare missing. Median =Rs.25 , Mode = Rs.24. calculate the missing frequency and hence the find mean.

how to find xi?

1. Observe the information's in the following cumilative frequency table

no. of days absentless than 5

less than 10

less than 15

less than 20

less than 25

less than 30

less than 35

less than 40

less than 45

No. of students29224465582634644650653655Q.. Draw a 'less than' ogive and 'more than' ogive to represent the above data .

Q... Find median for the above data by interpreting the graph.

Q...why regularity is essential in students life (VBQ)

What is the formula to use median when more than ogive is given?

Calculate the mean, median and mode of the following frequency

distribution:Classintervals:15 - 20 20 - 25 25 - 30 30 - 35 35 - 40 40 45 45 - 50 50 55Frequency: 3 8 9 10 4 3 2 1Draw the less than and more than O give (Cumulative Frequency Curve) for theabove data and hence find the median.median.

Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90

frequency 10 8 12 24 6 25 15

Find the value of f1 from the following data if it's mode is 65:

Class frequency

0-20 6

20-40 8

40-60 f1

60-80 12

80-100 6

100-120 5

Where frequency 6,8, f1, and 12 are in ascending order.

A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Number of days0 − 6

6 − 10

10 − 14

14 − 20

20 − 28

28 − 38

38 − 40

Number of students11

10

7

4

4

3

1

_{i}=100 , h=10 and f_{i}u_{i}= -30 , then find the mean of following distribution.PLEASE ANSWER FAST.

Marks Below 10 Below 20 Below 30 Below 40 Below 50 Below 60 Below 70 Below 80 Below 90 Below 100

No. of students 5 9 17 29 45 60 70 78 83 85

family size:0-4,4-8,8-12,12-16,16-20

number of families:8,14,12,4,2

find median and mode.

3 Median = Mode + 2 Mean

please proof it.

calculate the aritemetic mean,for the following frequency distribution

class interval frequency

0-80 22

80-160 35

160-240 44

240-320 25

320-400 24

In a continuous frequency distribution, the median of the data is 21.If each observation is increased by 5 find the new median

Class Interval

20-30

30-40

40-50

50-60

60-70

Frequency

25

47

62

p

10

The mean and median of same data are 24 and 26 respectively. The value of mode is ?

_{1 }, f_{2}and f_{3}in the following frequency distribution , when it is given taht f_{2 }: f_{3}= 4 : 3 , and mean = 5020-40

40-60

60-80

80-100

17

f

_{1}f

_{2}f

_{3 19}marks number of students

0 and above 80

10 and above 77

20 and above 72

30 and above 65

40 and above 55

50 and above 43

60 and above 28

70 and above 16

80 and above 10

90 and above 8

100 and above 0

if the median salary of 100 employees of a factory is 24800, then find the missing frequencies f

_{1}and f

_{2 }in the given dataSalary 10000-15000 15000-20000 20000-25000 25000-30000 30000-35000 35000-40000

frequen. 18 f1 f2 15 12 22

The following distribution gives the daily income of 50 workers of a factory.

Daily income (in Rs)100 − 120

120 − 140

140 − 160

160 − 180

180 − 200

Number of workers12

14

8

6

10

Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.

in a grouped frequency distribution,the class with the maximum frequency is called?

a.mean class b.median class c.modal class d.distribution class

the mean of first n odd natural numbers is n2/81,then n=

if the mean of the following frequency distribution is 91, find the missing frequency x and y :

classes frequency

0 - 30 12

30-60 21

60 - 90 x

90 -120 52

120 - 150 y

150 - 180 11

total 150

The mean of n observations is X . IF the first item is increased by 1, second by 2 and so on, then the new mean is:

1. X+n

2. X+n/2

3. X+(n+1)/2

4. X+(n-1)/2

The median of the following incomplete frequency distribution is 4 :

x= 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8

f= 2 , 3 , 4 , 1 , 2 , 4 , 2 , x

the frequency of 8 is : A) 1 B) 2 C) 3 D) 4 plz ans fastt....

class frequency

40-50 5

50-60 x

60-70 15

70-80 2

80-90 7

how do we find mean using step deviation method if the classes are unequal?

should we make the classes equal in such a case?

In a school , IQ of 250 students of class 10 are given in the following frequency distribution

IQ 120-130 130-140 140-150 150-160 160-170

no.10 80 100 50 10. Find the mean IQ of students .

of

students

During the medical check-up of 35 students of a class, their weights were recorded as follows:

Weight (in kg)Number of studentsLess than 38

0

Less than 40

3

Less than 42

5

Less than 44

9

Less than 46

14

Less than 48

28

Less than 50

32

Less than 52

35

Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.

Class interval Frequency0-10 10

10-20 20

20-30 x

30-40 40

40-50 y

50-60 25

60-70 15

.Find the median when mean = 20 and mode = 18.is it 19.3 cm ?

Find the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 from

their mean.

the interest paid on each of the three different sums of money yeilding 1%, 2% and 4% simple interest per annum respectively, is the same. find the average yield percent on the total sum inverted.

Class interval Frequency10-20 12

20-30 30

30-40 f1

40-50 65

50-60 f2

60-70 25

70-80 18

no links plz.

## Compute the median from the data

mid value 115 125 135 145 155 165 175 185

frequency 6 25 48 72 116 60 38 22

the median of the data is 525. find x and y, if total frequency is 100

class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000

frequeency 2 5 x 12 17 20 y 9 7 4

If median salary of 100 employees of a factory isrupees 24800, the find the missing frequencies f1 and f2 in the given distribution table:

Salary 10000- 15000- 20000- 25000- 30000- 35000-

(I

n Rupees) 15000 20000 25000 30000 35000 40000

Number 18 f1 f2 15 12 22

of employees

9. If the mean of the distribution is 57.6 and the sum of its observations is 50, find the missing

p' if the mean of the given data is 15.45.pThe mean of the following frequency dristibution is 50. Find the value of

ppf_{0}= frequency of the class preceding the modal class andf_{2}= frequency of the class succeeding the modal class and how to use them to calculate mode when grouped data is given please tell its urgentIn a school 85 boys and 35 girls appeared in a public examination . The mean marks of the boys were found to be 40 % whereas the mean marks of the girls were 60% . Determine the average marks % of the school.

Class Interval 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 90- 100

frequency 2 5 X 12 17 20 Y 9 7 4

how can we find the median by only less than ogive curve?

in a health check up , the nuber of heart beats of 40 women were recorded in the following table:

-no.of heart beats per minute | 65-69 | 70-74 | 75-79 | 79-84 |

- no of women | 2 | 18 | 16 | 4 |

find the mean of the data.

The median of the following data is 32.5.find the value of x and y

class interval f

0-10 x

10-20 5

20-30 9

30-40 12

40-50 y

50-603

60-70 2

total 40

The following table shows the marks obtained by 100 students of class X in a school during a particular academic session. Find the mode of this distribution.

Marks No. of studentsLess than 10 7

Less than 20 21

Less than 30 34

Less than 40 46

Less than 50 66

Less than 60 77

Less than 70 92

Less than 80 100

Q. If the mean of the following frequency distribution is 65.6. Find the missing frequency F

_{1}and F_{2}_{ }.Find the mean, mode and median for the following data.

Daily wage 200-300 , 300-400 , 400-500 , 500-600 , 600-700 , 700-800

number of workers 16 , X ,17, 20, 15, Y

Please reply fast........

The median of the following data is 20.75. Find the missing frequencies x and y, if the total frequency is 100.

Class interval:-0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40

Frequencies: -7 10 x 13 y 10 14 9

the mean mark obtained by 25 student of section A of class X is 47 and that of 35 student of section B is 51 and that of 30 student of section C is 53. find the mean of the marks scored by 90 student.

how to find the median class?

How to find missing frequency if the mode of the given data is given.

Classes Frequency

0-5 7

5-10 6

10-15 f

15-20 4

20-25 3

a) f <8

b) f

>8c) f > 8 only

d) f<7

How to convert a

LESS THAN OGIVEand it'sCFinto the Frequency distribution?Find the class marks of classes 10 - 25 and 35 - 55.The mean of 30 numbers is 18, what will be the new mean, if each number is increased by 3.

If the less than ogive and more than ogive intersect each other at ( 20.5,15.5 ), then the median of the given data is :

A ) 36.0 B) 20.5 C ) 15.5 D ) 5.5

The median from the table is

value 7, 8, 9, 10, 11, 12 ,13

frequency 2, 1, 4, 5, 6, 1, 3

If the mean of the following distributions is 27, Find the value of p

The mean of the following data is 53, find the missing frequencies.

age in years -- 0-20, 20-40 40-60 60-80, 80-100

number of people--- 15, f1, 21, f2, 17, 100

what is the need to use the sigma sign in the formula of mean??????????????

Total = 50

height in cm frequency cumulative frequency

150-155 12 a

155-160 b 25

160-165 10 c

165-170 d 43

170-175 e 48

175-180 2 f

In a given data if the MODAL CLASS is at the bottom(last) and has nothing Preceeding it then how will we find the MODE?

the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find

a) class size

b) lower limit of second class

c) upper lmit of last class

d) third class

what is summision?