Call me

Have a Query? We will call you right away.

+91

E.g: 9876543210, 01112345678

We will give you a call shortly, Thank You

Office hours: 9:00 am to 9:00 pm IST (7 days a week)

What are you looking for?

Syllabus

In fig Op is equal to diameter of the circle. Prove that abp is a equilateral triangle..

sry abt the figure but i dnt know how to upload the figure

But its a circle with two tangents AP and BP... and joining OP, OA and OB ( o is the centre of the circle... )

Two spherical balls lie on the ground touching ,if one ball has a radius of 8 units and the point of contact is 10 units above the ground what is the radius of the other ball?

OPQR is a rhombus, three of whose vertices lie on a circle with centre O. If the area of the rhombus is 32 (under-root)3 cm

^{2}, find the radius of the circle.THE PERIMETER OF A SECTOR OF A CIRCLE WITH CENTRAL ANGLE 90* IS 25CM FIND THE AREA OF THE MINOR SEGMENT OF THE CIRCLE.The wheels of a car are of diameter 80 cm each. How many complete revolutions does each wheel make in 10 minutes when the car is traveling at a speed of 66 km per hour?

please write in a simple method?

the long and short hands of a clock are 6cm and 4cm respectively.Find the sum of distances travelled by their tips in a day

PQRS is a diameter of a circle of radius 6cm. The lengths PQ, QR and RS are equal. Semi circles are drawn on PQ and QS as diameters. Find the perimeter and area of the region so obtained.

a motor cycle has diameter 91cm there are 22 spokes in the wheel find the length of the arc between the 2 adjoining spokes

The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

The cost of planting grass in a circular park at the rate of Rs 4.90/m

^{2 }is Rs 24, 640. A path of uniform width runs around the park. The cost of gravelling the path at the rate of rs 3.50/m^{2}is Rs 3696. Find the cost of fencing the path on both sides at the rate of Rs 2.10/mABC is a right angled triangle, angle B=90* ,AB=28cm and BC=21cm. With AC as diameter a semicircle is drawn and with BC as radius a quarter cicle is drawn. Find the area of the shaded region

Given: ABCD is a square

Find : Area of the shaded region

Two circular flower beds have been shown on two sides of a square lawn ABCD of side 56 cm. If the centre of each circular flower bed is the point of intersection O of the diagonals of of the square lawn, find the sum of the areas of the lawn and flower beds.

The question for the answer is: In a circular table of radius 32 cm, a design is formed leaving an equilateral triangle ABC in the middle as shown in the given figure. Find the area of the design(shaded region)

In the given figure, a square OABC is inscribed in a quadrant OPBQ. If OA = 20 cm, find the area of the shaded region. [Use π = 3.14]

1. Find the area of the shaded region in the figure if AC=24 cm ,BC=10 cm and o is the center of the circle (use

o

A [Ans- 145.33 cm

^{2}]a) 48 cm2 b) 80 cm2 c) 48 p cm2 d) 80 p cm2

Three circles of radius 2 cm touch one another externally. These circles are circumscribed by a circle of radius x. Find the value of x and the area of shaded region

ABCD is a trapezium with AB parallel to CD. AB=18cm, DC=32cm and distance between AB and DC=14cm. If arcs of equal radii 7cm with centres A,B,C and D have been drawn, then find the remaining area i.e. area exuding the circular region

PQRS is a diameter of a circle of radius 6 cm . The lengths PQ , QR , AND RS are equal. semi circles are drawn on PQ and QS as diameter. Find the perimeter and area of the shaded portion,

AB=36 cm and M is the mid-point of AB. Semicircles are drawn on AB,AM and Mb as diametrs.A circle with centre C touches all the three circles. Find the area of the shaded region.

M

pls explain me

An elastic belt is placed round the rim of a pulley of radius 5 cm. One point on the belt is pulled directly away from the centre O of the pulley until it is at P, 10 cm from O.find the length of the belt that is in contact with the rim of the pulley.

In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.

Acircular tablecloth of radius 30cm is to made .There should be two circular designed strips of width 5 cm each and width in between these strips is to be 5cm.. The radius of the inner circular plane portions is 10 cm. Find the total cost of making the two designed strips at the rate of Rs 0.75 per cm

^{2.}two circles touch internally, the sum of their areas is 116 pie sq cm and distances between their centres is 6cm. find the radii of the circles.

plzzzzz ans!!!! its urgent!!!

A rail road curve is to be laid out on a circle. If the track is to change direction by 28 degrees in a distance of 44 metres. Find the radius of the curve (in metre).

The boundary of the shaded region in the figure given consists of four semi-circular arcs, the smallest two being equal. If the diameter of the larger is 14 cm and of the smallest is 3·5 cm, calculate the length of the boundary and the area of the shaded region. (Take = 22/7).

1] the perimeter of a quadrant of a circle of radius ' r ' is ___________.

2] Area of a quadrant of circle whose circomference is 22cm is ____________.

in the fig O is the centre of circle with AC =24cm and AB=7 cm. and angle BOD =90. find the area of the shaded region..

NOT ABLE TO UPLOAD THE DIAGRAM....

its like a circle a diamete.two semicircles are thus formed.

one upper side of the diameter a triangleABC is formed with BC as its base n BC is the diameter...the on the lower side of the diameter the portion i.e the semicircle is biscetedby OD the radius...

IN the triangle AB is the smallest side AB the longest n AC the shortest...

pls make it as soon as possible tommorow is my maths exam...pls

In a circular table cover of radius 32 cm, a design is formed leaving an equilateral triangle ABC in the middle as shown in the given figure. Find the area of the design (Shaded region).

A, express the length of the chord in terms of A.

A chord of a circle of radius 12 cm subtends an angle of 120° at the centre. Find the area of the corresponding segment of the circle. please explain me in easy way?

A paper is in the form of a rectangle ABCD in which AB = 18 cm and BC = 14 cm. A semi-circular portion with BC as diameter is cut off. Find the area of a remaining part.

In figure, ABC is a right angled triangle, right angled at A. Semicircles are drawn on AB, AC and BC as diameters. Find the area of the shaded region.

Please see the figure:http://puu.sh/2e9qw

While doing dusting a maid found a button whose upper face is of black colour, as shown in the figure. The diameter of each of the smaller identical circles is 1/4 of the diameter of the larger circle whose radius is 16 cm.

Based on the above information, answer the following questions.

(i) The area of each of the smaller circle is

(a) 40.28 cm^{2}(b) 46.39 cm^{2}(c) 50.28 cm^{2}(d) 52.3 cm^{2}(ii) The area of the larger circle is

(a) 804.57 cm^{2}(b) 704.57 cm^{2}(c) 855.57 cm^{2}(d) 990.57 cm^{2}(iii) The area of the black colour region is

(a) 600.45 cm^{2}(b) 603.45 cm^{2}(c) 610.45 cm^{2}(d) 623.45 cm^{2}(iv) The area of quadrant of a smaller circle is

(a) 11.57 cm^{2}(b) 13.68 cm^{2}(c) 12 cm^{2}(d) 12.57 cm^{2}(v) If two concentric circles are of radii 2 cm and 5 cm, then the area between them is

(a) 60 cm^{2}(b) 63 cm^{2}(c) 66 cm^{2}(d) 68 cm^{2}a wooden article was made by scooping out a hemisphere from each end of a solid cylinder.I the height of the cylinder is 10cm and it's base radius is 3.5cm. find it total s.a.

The diagram shows a right angled triangle and a semi circle. PQ is the diameter of the semicircle. The perimeter of the whole diagam is... (a) 30 + 5pi (b)18 +6pi (c) 18 + 10pi

Find the area of the shaded region in the given figure, where a circular arc of radius 6 cm has been drawn with vertex O of an equilateral triangle OAB of side 12 cm as centre.

The area of a circle inscribed in an equilateral triangle is 154 cm2. Find the perimeter of the triangle.

Find the area of the shaded region in the following figure.

It is a square with each side of 4cm and there are two quadrants.

THE LENGTH OF THE MINUTE HAND OF A CLOCK IS 6.3CM . FIND THE AREA SWEPT BY THE MINUTE HAND DURING THE TIME PERIOD 5:45AM TO 6:10 AM AD ALSO FIND THE DISTANCE DISTANCE TRAVELLED BY THE MINUTE HAND DURING THIS PERIOD.The inner circumference of the circular track is 440 m and the track is 14 m wide.Calculate the cost of levelling the track at the rate of 25 paise per sq. m.Also, find the cost of fencing the outer circle at the of Rs. 5 per m.[Use pi = 22/7]

A wire when bent in the form of an equilateral triangle encloses an area of 121 √3 cm

^{2}. If the same wire is bent in the form of a circle, find the area of the circleIn an equilateral triangle of side 24cm , a circle is inscribed touching its sides . Find the area of the remaining portion of the triangle .

how to solve this. The area of the triangle is 5 sq.units,Two of its vertices are (2,1)and (3,-2).T he third vertix lies on y =x+3.Find the third vertex

1)find the probability of getting a non defective set 1

2)find the probability of getting a non defective set2

experts pls... help..!!

Fig shows a sector of a circle, centre O containing an angle θ.

Find the perimeter and area of the shaded region.

find i) perimeter = r (tan θ + sec θ + πθ/180 – 1)

ii)Area = r2/2(tan θ – πθ /180)

i need fully solved ..........hurry please....

an archery target has 3 regions formed by three concentric circles. if the diameters of the concentric circles are in the ratio 1:2:3, then find the ratio of the areas of the regions???guys plz help me....

need this answer before 10:30 am today...

Find the area of a quadrant of a circle whose circumference is 22cm.

The circumference of a circle exceeds its diameter by 16.8 cm. Find the circumfrence of the circle.

all the vertices of a rhombus lie on a circle. find the area of the rhombus if the area of the circle is 1256cm

^{2}1. the shape of the top of a table in a restaurant is that of a sector of a circle with centre O an dang;e bod=90. if bo=od=60cm, find the area of the table and the perimeter of the table top.

2. triangle ABC is right angled at A. semicircles are drawn on AB, AC and BC as diameters. find the area of the shaded region .

3.OPQR is a rhombus , three of whose vertices lie on a circle with centre O. if the area of the rhombus is 32root3 cm sq. , find the radius of the circle.

4.O is the centre of the biggre circle an dAC is the diameter. another circle with AB as diameter is drawn. if AC=54cm and BC=10cm, find the area of the shaded region.

a bicycle wheel makes 5000 revolutions in moving 11km find diameter of the wheel

what will be the increase in area of circle if its radius is increased by 40%???????

Q=AB is the diameter of a circle,center O .C is a point on the circumference such that /-COB=a.The area of minor segment cut off by AC is equal to twice the area of the sector BOC. Prove thatsin a/2 cos a/2 =pie(1/2- a/120)A boy is cycling such that the wheels of the cycle are making 140 revolutions per minute. If the diameter of the wheel is 60cm,calculate the speed per hour with which the boy is cycling.

Please help! :O

With vertices A,B and C of a triangle ABC as centres, arcs are drawn with 5cm each. With sides AB=14cm, BC=48cm and CA =50cm, find Area of whole triangle minus the sum of the three sectors

ABCD is a trapezium AB ||DC and angle BCD =60 degree.if befc is sector with center C and ab=bc=7cm and de=4 cm ,then find the area of the shaded region?

Two Concentric Circles of radii A and B ( A>B) are given. the Chord AB of larger circle touches the smaller circle at C. The length of AB is

The inside perimetre of a running track is 400m. The length of each of the straight portion is 90m and the ends are semi-circles. If the track is everywhere 14m wide, find the area of the track. Also find the length of the outer running track.

If a, b and c are the sides of a right angle triangle where C is the hypotenuse. Prove that radius, r of the circle touches the sides of the triangle given by

r=a+b-c2write the formula for the area of a segment in a circle, a circle of radius r, given that the sector angle is theta (in degrees). the answer to this is [pi theta/360- sin theta /2 cos theta /2] r2 as given in r.d. sharma. I can't understand how the formula derived.....

experts plzzz help me in dis question.....

^{0}and 150^{0}respectively. Find the ratio between the areas of the two sectors.ABCP is a quadrant of a circle of radius 14 cm With AC as a diameter, a semicircle is drawn. Find the area of the shaded region. (Take Pi=22/7)

The figure consists of a rt. angled triangle ABC, with AC as the hypotenuse. A semicircle APC is drawn with AC as the diameter. Over this, another the arc of the quadrant extends. The shaded region is between the arc of the semicircle and the arc of the quadrant.

what is the formula of area of minor segment and major segment?

The area of an equilateral triangle ABC is 17320.5 cm

^{2}. With each vertex of the triangle as centre, a circle is drawn with radius equal to half the length of the side of the triangle (See the given figure). Find the area of shaded region. [Use π = 3.14 and]plz answer this question....and plz tell me step by step......can anyone...help me..

Find the cost of fencing a circular field of area 9856m square at the rate of Rs 20 per metre..

in a circle with centre o.the area of sector oAPB is 5/18 of the area find the area of x

an equilateral triangle abc of side 6 cm has been inscribed in a circle . find the area of the shaded region . thai is the remaining part of the circle

In RD Sharma Chapter 15 : Areas related to circles: Revision exercise Question 32, how is the radius of the circle with centre C ,1/6th of AB ..???

the area of shaded region between two concentric circles is 286cm

^{2}. if the diffrence of the radii of the two circles is 7cm, find the sum of their radii ............ plzz replyis 25π cm

,then AB is equal to

(a) 5 cm (b) 8 cm (c) 10 cm (d) 25 cm

3 circles each of radius 3.5 cm are drawn in such a way that each of them touches the other two . find the area enclosed between these three cicles (shaded region )use pie=22/7?

Here, in this question's answer they have found the radius of the incircle by the formula bc/(a+b+c) for the sides of the triangle namely a(hypotenuse BC), b(AC) and c(AB).

Please explain this formula to me? Also, is this formula valid for all the triangles or just for right triangles?