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Tushil Pawar asked a question
Subject: Maths, asked on on 28/2/17
For square matrix A show that |adj(adjA)|= |A|^(n-1)^2
Karan Thobhani asked a question
Subject: Maths, asked on on 23/4/17
Investigate for what values of λ, ​μ the simultaneous equations x + y +z = 6; x + 2y + 3z = 10 & x + 2y +  λz = μ have :
(a) A unique solution.         (b) An infinite number of solutions.                    (c) No solution.
Karan Thobhani asked a question
Subject: Maths, asked on on 23/4/17
For what values of p, the equations : x + y + z = 1; x + 2y + 4z = p & x + 4y + 10z = p2 have a solution? Solve them completely in each case.
Karan Thobhani asked a question
Subject: Maths, asked on on 23/4/17
Solve the following sets of equations using Cramer's rule and remark about theit consistency.
(a) x + y + z - 6 = 0
    2x + y - z - 1 = 0
    x + y - 2z + 3 = 0

(b) x + 2y + z = 1
    3x + y + z = 6
    x + 2y = 0

(c) x - 3y + z = 2
    3x + y + z = 6
    5x + y + 3z = 3

(d) 7x - 7y + 5z = 3
    3x + y + 5z = 7
   2x + 3y + 5z = 5
Tushil Pawar asked a question
Subject: Maths, asked on on 28/2/17
If A is non singular then show that adj(adjA)= |A|^n-2 A
Karan Thobhani asked a question
Subject: Maths, asked on on 22/4/17
Prove that
(a) |ax by cz|    | a   b   c |                         (b) |1    a     a2-bc|
     |x2  y2  z2| = | x   y   z |                               |1     b     b2-ca| = 0
​     | 1   1   1|    | yz  zx xy|                              |1     c     c2-ab|
 
Karan Thobhani asked a question
Subject: Maths, asked on on 22/4/17
Without expanding the determinant prove that
(a) | 0   b   -c |                                               (b) | 0       p-q     p-r |
     |-b   0    a | = 0                                               | q-p     0       q-r | = 0
     |c   -a    0 |                                                      | r-p     r-q        0 |
Tanishka Gupta asked a question
Subject: Maths, asked on on 5/5/18
Solve que 11
Karan Thobhani asked a question
Subject: Maths, asked on on 22/4/17
The value of ​θ lying between -​π/4 & π/2 and 0​≤A≤π/2​ and satisfying the equation | 1+sin2A                cos2A                   2sin4​θ   |
                                                                                                     | sin2A       1+cos2A          2sin4θ  | = 0 
                                                                                                     | sin2A            cos2A       1+2sin4θ|
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