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Syllabus

(a) 4 (b) 2sin2 alpha

(c) -4sin2 alpha (d) 4sin2 alpha

In Traiangle ABC if b^{2}+c^{2}=3a^{2}. Then cotB+cotC-cotA equals to1. 1

2. ab/4 delta

3. 0

4. ac/4 delta

Ans and explanation

ABCD is a trapezium such that AB and CD are parallel and BC⊥CD. If ∠ADB = θ, BC = p and CD = q, then AB is equal to :

OptionsA)

B)

C)

D)

(a) b cot A (b) c cot A

(c) a cot A (d) a cot B

(a) sinA (b) tanA (c) sin

A(d) cosA(e) tanA2 2 2

a) There is a regular polygon with r/R=1/2,

b) There is regular polygon with r/R=1/rt2,

c) There is regular polygon with r/R=2/3,

d) There is regular polygon with r/R=rt3/2.

^{2}+4xy+y^{2}=0 is perpendicular to Lx+y+4=0 then L=?In ΔABC,andattains its maximum possible, then the equation whose are rootsandis

OptionsA)

B)

C)

D)

a cosA + b cosB + c cosC = r/R a + b + c

plzzzansfast

s. Then, the maximum area of the triangle isif abc is a triangle having a right angle at C and AE, BD are drawn perpendicularly to AB meet BC and AC produced in E and D respectively then prove that tan CED =tan^3 bac

Solve this :$59.Themostgeneralsolutionoftheequation\phantom{\rule{0ex}{0ex}}8{\mathrm{tan}}^{2}\frac{\theta}{2}=1+sec\theta ,is\phantom{\rule{0ex}{0ex}}\left(a\right)\theta =2n\mathrm{\pi}\pm {\mathrm{cos}}^{-1}\left(\frac{1}{3}\right)\left(\mathrm{b}\right)\mathrm{\theta}=2\mathrm{n}\mathrm{\pi}\pm \frac{\mathrm{\pi}}{6}\phantom{\rule{0ex}{0ex}}\left(\mathrm{c}\right)\mathrm{\theta}=2\mathrm{n}\mathrm{\pi}\pm {\mathrm{cos}}^{-1}\left(\frac{-1}{3}\right)\left(\mathrm{d}\right)\mathrm{None}\mathrm{of}\mathrm{these}$

A)

B)

C)

D)

None of these

Let the angles A, B and C of ΔABC be in A.P and.

Find the measure of angle C.

30°

45°

60°

90°

In ΔABC,andattains its maximum possible, then the equation whose are rootsandis

OptionsA)

B)

C)

D)

LetPQRbe a triangle of areawithand, wherea,bandcare the lengths of the sides of the triangle opposite to the angles atP,QandRrespectively. Thenequals

In ΔABC,andattains its maximum possible, then the equation whose are rootsandis