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derivative using first principle -

sin_/x

(sin under root x)^{2}. Please, it is 3x+2 not 3x-2. My previous was answered using 3x-2. But the question is 3x+2 in the denominator. Please answer to this question and let me know if the answer I provided from the textbook is right or wrong(-5/(3x-2)^{2}).Differentiate sinx/x from the first principle.

^{^}-x- 2)/x^2If x root (1+y) + y root (1+x) = 0

Prove that dy/dx = -1/(1+x)

^{2}experts do help!!

differentiate with respect to x

y = (x sin x) / (1+ cos x)

derivative of 1)logx by first principle

find dy/dx if y = 1/(ax + b)

find the derivative of

Find the derivative of root tanx from first principles.

Find the derivative of sinxcosx using first principles

evaluate:

lim x-0 [1-cosx (cos2x)^1/2] / x^2

how can we derivate cosecx by first principle

find derivative of log(cosx) w.r.t. 'x' using 1st principle

lim x tends to zero 1-cos4x / x

^{2}?find the value of k if lim x tends to 1 x^4-1/x-1 = lim x tends to k x^3-k^3/x^2-k^2

Find

integrate x^6+1/x^2+1

Lt (xsina- asinx)/(x-a)x--a

find the dervative of

find derivative of :-

e

^{root cot x }by first principle ?

Find derivative of sin2x,cos2x and tan2x using first principle

lim (x

^{7}-2x^{5}+1)/(x^{3}-3x^{2}+2)x-1Please give me the answer......

derivative of sin^n x

derivative of square root of cos x by first principle

lim. x->0

1- cosx.cos2x.cos3x /sin

^{2}2xFind dy/dx. If (x

^{2}+ y^{2})^{2}= xyFind the value of k if lim(x tends to 0) kx cosecx = lim(x tends to 0) x cosec(kx)

what is lim

_{x-0}x(e^{x}-1)/1-cosxdiscuss the continuity of function f(x)= |x|+|x-1| in interval [-1,2]

y= x tanx / sec x +tanx

differentiate x2 cosx from first principle..

lim cos2x - 1/cosx - 1

evaluate:

lim x-0 [(3^2x)-(2^3x)] / x

find the derivative of cosx by first principle of derivative

cos3x + 3 cos x / ( pi /2 - x )^3

evaluate lim h tends to 0 [ (a+h)^2 sin (a+h) - a^2sin a] / h

find derivative of sinX+cosX from first principle

lim

_{x }_{à }_{π/6 }= 2sin^{2}x + sinx – 1/ 2sin^{2}x – 3sinx + 1rs aggrawal solutions

evaluate sin x - sin a / x-a?

lim tan x-sinx / sin

^{3}xx--0

If y=(1-tanx/1+tanx) show that dy/dx=-2/1+sin2x

evaluate lim x-pi/4 (cox-sinx)/(x-pi/4)

√log{sin(x

^{2}/3 - 1)f(x)={1-coskx /xsinx ,x is not =0 and 1/2,x=0}

find k if limx-0f(x) = f(0)

evaluate limit x tends to pi/2 tan 2x / x-pi/2?

evaluate sin x - sin a / x-a?

Differentiate w.r.t x by using first principle

i)xcosx

lim x-->0 (cos 3x-cos 5x)/x

^{2}lim x tends to pi/2 [x-pi/2 /cosx] is equal to

Differentiate the following by using first principle -

i). tan (2x + 1)

ii).

√tan xiii). x

^{2 }sin xlim (x+y) sec (x+y) -x sec x / y

y--0

prove that the exponential function, a^x is continous at every point (where a>0)

find dy/dx if y = whole sq.root of sin 2x.

Q=If a^{2}+ b^{2}=23ab,then prove that log(a+b/5) = 1/2 (loga + logb)Book Mathematics Class XI R.D.Sharma

Exercise 29.9, Qno- 29

Please send the solution

examine the continuity

f(x) =logx-log7/x-7 for x not equal to 7

=7 for x= 7 at x=7

Q1. For a certain value of c, $\underset{\mathrm{x}\to -\infty}{\mathrm{Lim}}\left[{\left({\mathrm{x}}^{5}+7{\mathrm{x}}^{4}+2\right)}^{\mathrm{c}}-\mathrm{x}\right]$ is finite & non zero. The value of c and the value of the limit is -

(A) 1/5,7/5 (B) 0, 1 (c) 1, 7/5 (D) none

tell me all the formulae of limits and derivatives of class 11th as well as 12th !!find dy/dx if y = log sinx.

lim x-> infinity{3x^2+1/4x^2-1}^ x^3/(1+x)

Q. lim x tends to pi/2

1+cos2x / (pi-2x)

^{2}Evaluate: lim x-->5 {(x-3)

^{5}- 32}/{x-5}^{2 }- x^{2 }) - (x^{2 }/4)] / x^{4 }, a > 0.x--0

If L is finite, then

a). a = 2; L = 1/64

b). a = 1; L = 1/64

c). a = 3; L = 1/32

d). a = 1; L = 1/32

Differentiate using first principle : e

^{[under root(tan x)]}Evaluate 1. lim x tends to zero root(2)--root(1+cosx) /sin square x

2. lim x tends to pai/2 (cos 3x+3cosx) / ( pai/2-x)whole cube

3.lim x tends to 2 (x/x-2 --- 4/xsqare - 2x)