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I HAVE SOME DOUBT IN THIS SOME

Answers

Let the point of contact of the tangent be (x1,y1) then

(x1,y1) lies ony= cos (x+y)

y1= cos (x1+y1) ... (1)

Since the tangents are parallel to the linex+ 2y= 0

Therefore,

Slope of the tangent of (x1,y1) = Slope of the linex+ 2y= 0

The equation of the curve is

y= cos (x+y)

Differentiating w.r.t.x, we get

Squaring (1) and (2) and then adding, we get

Puttingy1= 0 in (1) and (2) we get

Hence the point of contact are

∴ equation of tangents are

value of

i think value of x1 will be n/2 & 3n/2 not -3n/2 please clarify

Gauri Khanna asked a question
Subject: Maths, asked on on 3/7/14
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