5. a craft mela is organised by welfare association to promote the art and culture of tribal people. the pandal is todecorated by using string of bulbs all aroung the field . there are two options either to arrange it in a rectangular field . there are two options either to arrange it in rectangular field ABEF or parallelogrm ABCD with equal area

a. what shape of the field should be chosen to minimise the expense of bulb and why?

b. which values are depicted here ?

 ABCD is a trapezium in which AB is parallel to DC. DC=30 cm. and AB=50cm. if  X  and Y   are respectively the mid points of AD and BC, prove that     (Nine times the area of DCYX= seven times the area of XYBA.)

If a triangle is divided into four pieces with areas 8 , 5 , 10 and x then find x.

 if the medians of a triangle ABC intersect at G show that ar ( AGB ) = ar(AGC)=ar(BGC)=1/3 ar(ABC).

​

prove that two triangles having the same base (or equal bases) and equal areas lie between the same parallels.

ABCDE is a pentagon.A line passing through B parallel to AC meets DC produced at F.Show that

ar(ACB)=ar(ACF)

ar(AEDF)=ar(ABCDE)

explain with figure

prove that median divides triangle into two equal parts

 the base of a triangular field is three times its altitude.if the cost of sowing the field at rs 58 per hectare is rs 783,find its base and height.

The median BE and CF of a triangle ABC intersect at G. prove that area of triangle-GBC = area of quadrilateral AFGE.

Q. The side AB of a IIgm ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then IIgm PBQR is completed.Show that ar(IIgm ABCD) = ar(IIgm PBQR)

Diagonals AC and BD of trapezium ABCD with AB||DC intersect each other at O.

prove that ar(AOD) = ar (BOC)?

Let ABC be an equilateral triangle in which coordinates of B and C are (5,0) and (-5,0) respectively . Find the coordinates of the oint A.

 prove that the diagonals of a parallelogram divides into four triangle of an equal area

 ABCD is a trapezium with AB parallel to DC. a line parallel to AC intersects AB to X and BC to Y. prove that ar(ADX)=ar(ACY).

ABCD is a parallelogram in which BC is produced to E such that CE = BC(Fig. 9.17). AE intersects CD at F.If ar (DFB) = 3 cm2, find the area of the parallelogram ABCD.

 ABCD is a trapezium with AB||DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar(ADX)= ar(ACY)

in a triangle ABC,E is the midpoint of median AD. Show that area of BED = 1/4 area of ABC

XY is a line parallel to side BC of a triangle ABC. If BE || AC and CF || AB meet XY at E and F respectively, PLZ EXPERTS DRAW FIGURE BY GIVEN INFORMATION. my teacher tell me that there is not given that by where the line XY pass i.e whether it passes through A , or passess by intersecting side AB and AC so in exam which figure i should draw.

The diagonals of a parallelogram ABCD intersect at point O. Through O, a line is drawn to intersect

AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal areas.

Two triangles on the same base (or equal bases) and between the same parallels are equal in area . How do I prove this one ? :(

P and Q are respectively the mid points of side AB and BC of a triangle ABC and R is the mid point of AP show that,

{1} ar(PQR)= 1/2 ar(ARC)

{2} ar (RQC)=3/8 ar(ABC)

3) ar (pBQ) = ar(ARC)

ABCD is a parallelogram and BC is produced to point Q such that AD=CQ. If AQ intersects DC at P, show that ar(triangle BPC)=ar(triangle DPQ)

Prove that area of a rhombus is half the product of its diagonals.

Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that

[Hint: From A and C, draw perpendiculars to BD]

D is mid point of side BC of a triangle ABC and E is mid point of BD.If O is mid point of AE , then prove that ar(BOE)=1/8ar(ABC)

If E, F, G, H ar respectively the mid points of the sides of a parallelogram ABCD, show that ar(EFGH)= 1/2 ar(ABCD)

1) AD is the median of the triangle ABC. E is any point on AD. Show that ar(triangle BED) = ar(triangle CED).

2)ABCD is a parallelogram BA is produced to E such that AE = AD. ED is produced to meet BC produced at F. Show that CD = CF

Please help me with the above questions

Thank You

prove that a cyclic trapezium is always isosceles trapezium.

Prove that the line segment joining the mid-points of opposites sides of a quadrilateral bisect each other.

Please help me with these sums

The side AB of a parallelogram ABCD is produced to any point P. A line through A andparallel to CP meets CB produced at Q and then parallelogram PBQR is completed. Show that the area of ABCD = area of PBQR.

I think that the question is wrong, but it came in one of the previous years' question papers.

In a parallelogram PQRS, L and M are the mid-points of QR and RS respectively. Prove that :

ar(ΔPLM) = 3/8 ar( IIgm PQRS).

Please help. :)

in the fiqure ABCD and AEFD are two parallelograms. Prove that ar (PEA)=ar(QFD)

Parallelogram ABCD and rectangle ABEF are on the same base and have equal areas. Show the perimeter of parallelogram is greater than rectangle.

WHAT IS AREA AXIOMS,CONGRUENT AREA AXIOMS,AREA MONOTONE AXIOM,AREA ADDITION AXIOM AND RECTANGLE AREA AXIOM

ABC and BDE are two equilateral triangles such that D is the midpoint of BC .AE intersects BC in F.prove that::

1. ar(triangle BDE)=1/4 ar(triangle ABC)
2. ar (triangle BDE)=1/2 ar(triangle BAE)
3. ar (triangle BFE)= 2ar(triangle FED)
4. ar(triangle FED)=1/8 ar (triangle AFC)
5. ar(triangle ABC)=2ar(triangle BEC)
6. ar(triangle BFE)=ar (triangle AFD)
7. ar(triangle BFE)=2ar(triangle EFD)

If O is the circumcentre of Triangle ABC and OD prependicular to BC. Prove that

Angle BOD = Angle A

prove that in a triangle the line segment joining the mid points of any to sides is parallel to the third side.

Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that

ar ( AOD ) = ar ( BOC ). Prove that ABCD is a trapezium....!!

I GuARAnTEeEE ThUMBS uP* FoR De CrrCt aNsaZz... ;)

ABCD is a rectangle with 'o' as any point in its interior. if area of triangle AOD=3cm square and area triangle BOC= 6cm square then find the area of rectangle ABCD.

(1) D and E are points on sides AB and AC respectively of triangle ABC such that ar (DBC) = ar (EBC). Prove that DE//BC

(2) Diagnols AC and BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD) = ar (BOC). Prove that ABCD is a trapezium

(3) Diagnols AC and BD of a quadrilateral ABCD intersect each other at P. Show that ar (APB) x ar (CPD) = ar (APD) x ar (BPC)

CAN SOMEONE PLZZZZ GIVE THE ANSWERS TO THESE QUESTIONS .vryy imp...

ABCD is a parallelogram.P and Q on BC trisects it.Prove that ar(APQ) =ar(DPQ)=1/6ar(ABCD)

ABCD IS A TRAPEZIUM WITH PARELLEL SIDES AB=a AND CD=b E AND F ARE MIDPTS OF NON PARALLEL SIDES.THE RATIO OF ar(ABEF) = ar(EFCD)

 If each diagonal of a quadrilateral seperates it into two triangles of equal area, prove that the quadrilateral is a parallelogram.

P and Q are any two points lying on the side DC and AD respectively of a parallelogram ABCD.Show that ar(APB)=ar(BQC).....

p is a point in the interior of a parallelogram abcd show that

area apb +area pcd = 1/2 area abcd

area apd +area pbc =area apb+area pcd

An artist is designing a pattern of triangular tiles to cover a wall. Each section of the pattern is identical to the section shown here. If the wall is 576 cm long and 384 cm high, how many black tiles will the artist need to use on the wall ?

If the mid points of the sides of a quadrilateral are joined in order, prove that the are of the parallelogram so formed will be half of the area of the given quadrilateral. Please experts answer it as quickly as possible.

XY is a line parallel to side BC of a triangle ABC. If BEAC and CFAB meet at E and F repectively. Show that ar(ABE) = ar(ACF)

 In a cyclic quadrilateral PQRS if angle P-angleR =50degree then find the measure of angle p and angle r.

D, E and F are respectively the mid-points of the sides BC, CA and AB of a ΔABC. Show that

(i) BDEF is a parallelogram.

(ii) ar (DEF) = ar (ABC)

(iii) ar (BDEF) = ar (ABC)

Triangle ABC and DBC are on the same base BC with vertices A and D on opposite sides of BC such that area of triangle ABC = area of triangle DBC. Show that BC bisects AD

 O is any point on the diagonal PR of a parallelogram PQRS . prove that ar(PSO) = ar(PQO) .

 ABCD is a quadrilateral. A line through D,parallel to AC meets BC produced in P. Prove that  area of triangle APD= area  of quadrilateral ABCD.

i want a report on-compare the performance of two teams for one day cricket match statistically .

(1) performance of both teams to commulative scores.

(2) investigate the interval in which run rate was slow ,fast and average with all the wickets.

(3) compare the performance of individual players

ABCD IS A PARALLELOGRAM, G IS THE POINT ON AB SUCH THAT AG = 2GB, E IS A POINT OF CD SUCH THAT CE = 2DE AND AND F IS A POINT OF BC SUCH THAT BF = 2FC. PROVE THAT

1) ar(ADEG) = ar(GBCE), 2) ar(EGB) = 1/6 ar(ABCD) , 3) ar(EFC) = 1/2 ar(EBF) , 4) ar(EBG) = ar(EFC) , 5) FIND WHAT PORTION OF THE ARE OF PARALLELOGRAM IS THE AREA OF EFG.

A triangle ABC is right angled at A. AL is drawn perpendicular to BC. Prove that angle BAL = angle ACB

can anyone proof this theoram and tell me?

'IF TWO TRINGLES OF EQUAL AREAS LIE ON THE SAME BASE , THEN THEY SHOULD LIE BETWEEN THE SAME PARALLELS'.

 prove that parallelogram on the same base and between the same parallel are equal in area

In triangle PQR, PS and RT are medians and SM is parallel to RT. Prove that QM= 1/4 PQ.

The circumcentre of the triangle ABC is O. Prove that angle OBC+angle BAC=90 degree. Please answer fast!!!!!!

ABC and ABD are two Triangles on lthe same base AB. If line segment CD is bisected by AB at O, Show that ar(ABC) = ( ABD)

A point E is taken on the side BC of a parallelogram ABCD. AE and DC are produced to meet at F.

Prove that ar( ADF ) = ar (ABFC ).

​

In triangle ABC, AD is the median and DE || AB. Prove that BE is another median.

Please help! :O

Sorry, i couldn't post the figure.

in the given figure abcd is a parallelogram, ap is perpendicular to dc and cq is perpendicular to ad. if ab=10cm, ad=8cmand ap=8cm then cq=

 ABCD is a quadrilateral and DP//AC.Show that ar(ABP)=ar(ABCD)

The diagonals of quad. ABCD intersect at O .Prove that if BO = OD, then ar (triangle ABC) = ar (triangle ADC).

IN THE FIRST VIDEO,HOW  CAN ar(abcd) - 1/2 ar(abcd)..be subtracted???..plzz clear my doubt..i am not able to understand the first video...

If a triangle and a parallelogram are on the same base and between the same parallels, then prove that area of the triangle is equal to half the area of the parallelogram.

My teacher is saying that it is a theoram plz tell me by proving it...

 plz explain the 1 st sum in the lets review which is : in II^gm PQRS , RN is perpendicular to PS and PM  is perpendicular to SR .if PQ = 120 cm , PM =30root5 cm and RN = 180root5 cm , thn what is the measure of the side PS ?  plz answer ...

1. in triangle ABC.D id the mid-point of AB &P is any point on BC.if CQ is parallel to PD meets AB in Q,then prove that :-

ar(BPQ)=1/2ar(ABC

QUES-prove that the area of rhombus is equal to half the rectangle contained by its diagonal.

TO PROVE-ar(rhombus ABCD)=1/2(area of rect. contained by its diagonals) => 1/2(AC * BD)