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Syllabus
Q.74. In the parallelogram ABCD, M is mid-point of AC and X, Y are points on AB and DC respectively such that AX = CY.
Prove that :
(i) triangle AXM is congruent to triangle CYM,
(ii) KMY is a straight line.
1) M , N and A are collinear.
2) A is the mid point of MN.
Prove that
I) angle PQR = 90 DEGREE
II) Line through P and parallel to QR bisects side AD
Please do not provide any link.
If AO = 2CO and BO = 2DO; show that:
(i) ∆AOB is similar to ∆COD.
(ii) OA × OD = OB × OC.
(i) the actual length of the diagonal distance AC of the plot in km.
(ii) the actual area of the plot sq km.
Question: AB||DC, BC=AD=13cm, AB=22cm and DC=12cm. Calculate the height of the trapezium ABCD.
1. the actual length of the diagonal distance AC of the plot in km.
2. the actual area of the plot in sq km.
(b) In PQR, MN is parallel to QR and
(i) Find
(ii) Prove that OMN and
ORQ are similar.
(iii) Find , Area of OMN : Area of ORQ
Q. In triangle PQR, MN||QR and
(i) Find
(ii) Prove that triangle OMN and ORQ are similar
(iiI) Find, area of triangle OMN : area of triangle ORQ
A.33.33%
B.66.67%
C.25.33%
D.50.67%
(i) the length of PQ, if BC=7.5cm.
(ii)the area of triangle APQ: area of triangle ABC
(iii)the area of triangleAPQ:area of PBCQ