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Syllabus

Find the missing frequencies in the following frequency distribution whose mean is 50

X

10

30

50

70

90

Total

F

17

fi

32

F2

19

120

what is the correct formula for adjusted frequency because wile doing the examples on meritnation the formula used was:-

Adjusted frequency= frequency/class size*minimum class size

whereas in the video regarding the histogram where adjusted frequency was used the formula applied there was:-

Adjusted frequency= minimum class size/class size*frequency

what is the formula of mean , median , mode ?

62 , 65 , 68 , 70 , 72 , 74 , 76 , 78 , 80 , 82 , 96 , 101,

find

a) the median,

b) the first quartile,

c) the third quartile,

d) the interquartile range (IQR).

what is class, class size, class interval and class marks????? plz plz plz answer fast......or else i will fail.......plz

_{1+}x_{2}+.....x_{15}) / 15, then find the value of (x_{1}- M) / 15 + (x_{2}- M) /15 + (x_{3}- M) /15 +..... (x_{15}- M) /15In a frequency distribution, the mid-value of a class is 20 and the width of the class is 8.then what is the lower limit ?

If mean of 5 observations x , x+2 , x+4 , x+6 , x+8 is 11.

Find the median of first three observations.

How many cubes in all have three sides painted?

(a)?24

(b)?16

(c)?10

(d)?8

Plz help,

Find the missing frequencies f1 and f2 in the following frequeny distribution, if it is know that the mean of the distribution is 1.46

xi 0 1 2 345 total

fi 46 fi f2 25 10 5200

Xi 0 1 2 3 4 5

Xf 3 3 p 7 p-1 4

The mean of first 8 observations is 18 and last 8 observations is 20 . If the mean of all 15 observations is 19 , find the 8 th observation?

the two consecutive class marks of a distribution are 52 and 57. find the class limits of two intervals

The mean of 40 items is 35 and if each item is multiplied by ‘a’ then the new mean will be

(A) 35 a (B) 35 + a C) 40 D) 40 + a

whats the difference between class interval, class size,class limit,class mark and also ranges,width and length of rectangle ?

153, 140, 148, 150, 154, 142, 146, 147.

Pls do not give any links.

Find the value of p, if the mean of the following distribution is 20

x: 15 17 19 20+p 23

f: 2 3 4 5p 6

note : the method should be of sigma fixi.

_{i}x_{1}by sigma f_{i}?how too find class marks ??explain with an example ??

wat is histogram , expalin with an example !?expain who to find scale with example !???Differentiate between class limits and true class limits.Give examples

21. In the following groups of data, tell whether the mean or the median best describes the data:

(i) 6, 4, 2, 12, 2 (ii) 31, 28, 24, 9, 23 (iii) 45, 51, 47, 65, 36 (iv) 10, 20, 30, 100, 9

what is the exact formula for ADJUSTED FREQUENCY??????????????

BECAUSE 2 VIDEOS OF THE SAME CHAPTER BUT OF OTHER LESSON SHOW DIFFERENT FORMULA SO WHICH ONE IS CORRECT.

how to make class intervals continuous?

IS THERE ANY FORMULA TO CALCULATE LOWER CLASS LIMITS OF LOWER CLASS,UPPER CLASS LIMIT OF UPPER CLASS , LOWEST CLASS LIMIT UPEER CLASS LIMIT CLASS INTERVALS CLASS SIZE MID VALUEIF ANY OF THE TWO THINGS ARE GIVEN FROM THE ASKED ABOVE.

use of statistics in our daily life

the mean of 10 observations is 42 . if each observations is decreased by 12 find the new mean

If any one have taken Maths, Science or Hindi paper please send it to me on my id guptajpcf@gmail.com. For SST & English papers SA-2 2010-11 you can follow me "guptajpcf" at scribd.com and you can download paper. But remember to send requested papers. Thanks in advance.

Help,

The mean of 25 observatios is 36. Out of thes,if the mean of first 13 observation is 32 and that of last 13 observation is 40,find the 13th observation.

There are 120 students in a class in which 20 of them are girls and rest are boys. The average marks in mathematics of the boys is 65% and that of is 80%, find the average marks of the class

the mean of 15 numbers is 27 .if each number is multiplied by 4,what will be the mean of the new number

Class size = Difference between class marks of two consecutive classes.= 52 - 47 = 5

Lower-class limit = class marks - 1/2 of class size= 47+2.5 = 49.5

Upper class limit = class marks + 1/2 of class size = 52+2.5 = 54.5

Since, the class-limits form a continuous frequency distribution; the true class limits and the class-limits are the

same

Mean of 50 observations was found to be 80.4. But later on it was discovered that 96 was misread as 69 at one place. Find the correct mean. If to each observation a constant value k is added, how is the mean affected?

make frequency polygon

Score - 32-34 , 35-37 , 38-40 , 41-43 , 44-46 , 47-49 , 50-52 !

Frequency - 13 , 12 , 20 , 18 , 15 ,10 , 4 .

find the mean median of first 12 odd composite numbers

when is the jack line used in graphs????

A) 30

B)39

C)48

D)49

if the ratio of mean and median of a certain data is 2:3 , then find the ratio of its mode and mean.

Q1. In a family of seven persons there are three earning members having monthly income of Rs. 1800, Rs. 1400 and Rs. 1000. What is the average income of a member in a family?

Q2. The mean weight of 34 students of class 9th of a school is 42kg. If the weight of the teacher be included, the mean rises by 400gm. Find the weight of teacher.

Q3. the mean of six no. is 20. If one no. is excluded, the mean is 15. Find the value of the excluded no.

The following observation have been arranged in ascending order. if the median of the data is 63, find the value of x

29,32,48,50,x,x+2,72,84,95

the mean salary paid to 1000 workers of a factory was found to be Rs. 180.40 later it was discovered to the wages of two workers wrongly taken as Rs. 297 and Rs. 165 instead of Rs. 197 and Rs. 185 find the correct mean

design a crossword puzzle using mathematical terms

What is class mark and how is it calculated??

the class marks of distribution are

47,52,57,62,67,72,77,82 determine the class size,class limit,ture class limits.

the mean of five numbers is 30. if one number is excluded, their mean becomes 28. the excluded number is:

what is adjusted frequency ? why is it used ? please explain in detail.

Find the mean of factors of 24

For a particular year following is the distribution of ages (in years) of primary school teachers in a district

Age (in years)

15-20

20-25

25-30

30-35

35-40

40-45

45-50

No. of teachers

10

30

50

50

30

6

4

1) 1) Write the lower limit of first class interval

2) 2) Determine the class limits of the fourth class interval

3) 3) Find the class mark of the class 45-50

4) Determine the class-size

In a frequency distribution,mid value of a class is 10 and width of class is 6. The lower limit of the class isthe mean of 16 numbers is 8. If 2 is added to every number, what will be the new mean ?

Draw a histogram and the frequency polygon from the following data

Class interval

20-25

25-30

30-35

35-40

40-45

45-50

Frequency

30

24

52

28

46

10

If x is the number of hours a labourer is on work "and y is his wages in rupees then y=4x+3. Draw the work wages graph of this equation . From the graph , Find the wages of a labourer Who puts in 4 hours of work.

Use the assumed s mean method to find the mean height of the plants from the following frequency-distribution table

Height in cm (x1)

61

64

67

70

73

No. of plants (fi)

5

18

42

27

8

the class mark of a distribution are :

37,42,47,52,57

determine the class size and class limits......

X 50,60,70,80,90,100,110,120

Y 10,18,15,20,18, 6 , 12, 11

the mean of 5 number is 18 if one number is excluded, their mean is 16 .find the excluded number

a)95

b)25

c)70

d)60

how to convert the dis-continuous class into continuous class interval

Find the value of x and y in following distribution if it known that the mean of the distribution is 1.46

No. of students 0 1 2 3 4 5 Total

Frequency 46 x y 25 10 5 200

Both parts

the mean of 5 numbers is 7 if one more number is included the mean increases by 2. find the number included

if the mean of the observations x, x+3 ,x+5 ,x+7, and x+10 is 9. what is the mean of last three observations.

10 observations 6, 14, 15, 7, x+1, 2x-13, 30, 32, 34, 43 are written in ascending order. The median of the data is 24. Find the value of x.

find the mean median or mode:

2,3,4,5,0,1,3,3,4,3,

The mean of 12 numbers is 40. if each number is divided by 8 what will be the mean of the new number

mean of 50 obs. was found to be 80.4 but later on it was found that 96 was misread as 69 at one place . find the correct mean

how to find the class size and class interval when the class marks are given.pls tell fast....

the mean marks (out of 100)of boys and girls in an examinaiton are 70 and 73, respectiviely. if the mean marks of all the students in that examination is 71 find the ration of the mumber of boys to the no of girls

The mean of 20 numbers is 18. If 3 is added to each of the first ten numbers, find the mean of the new set of 20 numbers.

1. Let x be the mean of x

_{1}, x_{2}, ...x_{n}and y be the mean of y_{1}, y_{2}....y_{n}. If z is the mean of of x_{1}, x_{2}, ...x_{n'}y_{1}, y_{2}....y_{n}. then z is equal to?2. If each observation is increased by 5, then their mean

(a) remains the same (b)becomes 5 times the original mean (c) is decreased by 5 (d) is increased by 5.

Please answer with explanation.

Give one example of a SITUATION where:

i. mean is an appropriate measure of central tendency.

ii. median is an appropriate measure of central tendency but mean is not.

The mean weight of 8 numbers is 15, if each number is multiplied by 2, what will be the new mean

There are 100 students in class 40 of them are girls, the average marks of the boys in science is 75% and that of girls is 65% find the average marks of class in science.

find the mean of the following data by shortcut method

what is the mean of first five natural numbers

The mean 20 observation is 25. In each observation is multiplied by 2. What is the new mean of Observation?????/

sector of angle 96°, then the percentage of the

component value in the total is

The mean of 200 items was 50. Later on it was discovered that 2 items were misread as 92 and 8 instead of 192 and 88. Find the correct mean.

Fast plz