Call me

Have a Query? We will call you right away.

+91

E.g: 9876543210, 01112345678

We will give you a call shortly, Thank You

Office hours: 9:00 am to 9:00 pm IST (7 days a week)

What are you looking for?

Syllabus

A)100m

B)200m

C)300m

D)400m

1)6N& 8N

2)7N & root 51N

3)6root2& 2root7

4)9N & 1N

_{0}so that theparticle hits the inclined plane perpendicularly.

(a) ${\mathrm{v}}_{0}=\sqrt{\frac{2\mathrm{gH}}{5}}$ (b) ${\mathrm{v}}_{0}=\sqrt{\frac{2\mathrm{gH}}{7}}$ (c) ${\mathrm{v}}_{0}=\sqrt{\frac{\mathrm{gH}}{5}}$ (d) ${\mathrm{v}}_{0}=\sqrt{\frac{\mathrm{gH}}{7}}$

^{2}Q.21. A retarding force F = - 2v is acting on a body of mass 10 gram. Find out time taken for its velocity to reduce to 37 % of its initial value if initial velocity is 1 m/s.

(1) 2.5 ms

(2) 5 ms

(3) 7.5 ms

(4) 8 ms

(1) 0.2 kg-m/s (2) –0.2 kg-m/s (3) 0.1 kg-m/s (4) –0.4 kg-m/

A person watching through the window of an apartment sees a ball that rises vertically up then vertically down for a total time of 0.5 sec. If the height of the window is 2m find maximum height above the window reached by the ball?(g=10 m/s^2)

4.A particle rotates along a circle of radius $R=\sqrt{2}mwithanangularacceleration\alpha =\frac{\mathrm{\pi}}{4}rod/{s}^{2}$ starting from rest. Calculate the magnitude of average velocity of the particle over the time it rotates a quarter circle.2. A ball is thrown from the roof of a building of height 44m with speed 4

_{0}at the angle $\theta $ below the horizontal. it lands 2 seconds later at a point 30m from the base of the building, then the value of tan $\theta $ is : (g=10 m/s^{2})$\left(\mathrm{A}\right)\frac{4}{5}\left(\mathrm{B}\right)\frac{3}{5}\left(\mathrm{C}\right)\frac{5}{4}\left(\mathrm{D}\right)\frac{5}{3}$

1 9.8m/s 2 4.9m/s 3 9.8(sqrt2)m/s 4 4.9(sqrt2)m/s

^{2}. A is a point lying exactly on the middle of the semi-circle track as shown in the fig. When the particle reaches A. Find The magnitude of velocity vector of the particle at the instant.^{2}-4t+6) m. the distance travelled by body in time interval t=0 to t=3s isa target is fixed on top of a pole 13m high. a man is standing at a distance 50m from the pole is capable of projecting a stone with velocity 10√g m/s. if he wants to wants to strike the target at shortest possible time, at what angle should he project the stone???????

^{2}. what speed will attain in 10 sec.plezzzz help

^{o}. The mass of the bob is 100 g.finda) the centripetal force acting on the bob.

b) linear speed of the bob

We say that object is going downwards hence it is negetive, but what

makes direction downward?if the answer is gravity thenwhat if object is in space is there is any downward√a target is fixed on top of a pole 13m high. a man is standing at a distance 50m from the pole is capable of projecting a stone with velocity 10√g m/s. if he wants to wants to strike the target at shortest possible time, at what angle should he project the stone???????

12. A platform is pulled with a constant acceleration a A particle is projected from the platform at angle $\theta $ with the horizontal with respect to the platform as shown in the figure. The value of tan$\theta $ such tha particle again come to the starting point on the platform is (a=5 m/s

^{2}): use g = 10 m/s^{2}(A) 4 (B) 6 (C) 2 (D) 3

a) radius of circular path

b) tension in string

$\left(1\right)0\xb0\phantom{\rule{0ex}{0ex}}\left(2\right)90\xb0\phantom{\rule{0ex}{0ex}}\left(3\right)30\xb0\phantom{\rule{0ex}{0ex}}\left(4\right)60\xb0$