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In fig Op is equal to diameter of the circle. Prove that abp is a equilateral triangle..

sry abt the figure but i dnt know how to upload the figure

But its a circle with two tangents AP and BP... and joining OP, OA and OB ( o is the centre of the circle... )

OPQR is a rhombus, three of whose vertices lie on a circle with centre O. If the area of the rhombus is 32 (under-root)3 cm

^{2}, find the radius of the circle.The wheels of a car are of diameter 80 cm each. How many complete revolutions does each wheel make in 10 minutes when the car is traveling at a speed of 66 km per hour?

please write in a simple method?

(i) the sum of the areas of the two shaded segments made by the chords AB and BC.

(ii) the area of the shaded segment made by the chord PQ. $\left[take,\mathrm{\pi}=\frac{22}{7}\right]$

PQRS is a diameter of a circle of radius 6cm. The lengths PQ, QR and RS are equal. Semi circles are drawn on PQ and QS as diameters. Find the perimeter and area of the region so obtained.

A wire, in the shape of an equilateral triangle,encloses an area 'A' cm

^{2}. if the same wire is bent to form circle then the area of the circle will be:(A) a

^{2}/22/7 (B) 2A^{2}/22/7 (C) 3A/22/7 (D) 3Aroot3/22/7The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

Another circle XYZ with centre P, is enclosed by the sector OAB. If angle AOB= 60 Find the area of OXPY.

ABC is a right angled triangle, angle B=90* ,AB=28cm and BC=21cm. With AC as diameter a semicircle is drawn and with BC as radius a quarter cicle is drawn. Find the area of the shaded region

Its for Class 10th CBSE student...

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Two circular flower beds have been shown on two sides of a square lawn ABCD of side 56 cm. If the centre of each circular flower bed is the point of intersection O of the diagonals of of the square lawn, find the sum of the areas of the lawn and flower beds.

In a rectangle of dimension 14*7, Two semicircles are drawn by taking midpoints of the lengths of the rectangle as the centres.

Find the area of rectangle which is not common to both of these semicircles.

In the given figure, a square OABC is inscribed in a quadrant OPBQ. If OA = 20 cm, find the area of the shaded region. [Use π = 3.14]

THE PERIMETER OF A SECTOR OF A CIRCLE WITH CENTRAL ANGLE 90* IS 25CM FIND THE AREA OF THE MINOR SEGMENT OF THE CIRCLE.the long and short hands of a clock are 6cm and 4cm respectively.Find the sum of distances travelled by their tips in a day

find the perimeter of shaded region if ABCD is a square of side 14 cm and APBand CPDare semicircles.

Three circles of radius 2 cm touch one another externally. These circles are circumscribed by a circle of radius x. Find the value of x and the area of shaded region

A, express the length of the chord in terms of A.

ABCD is a trapezium with AB parallel to CD. AB=18cm, DC=32cm and distance between AB and DC=14cm. If arcs of equal radii 7cm with centres A,B,C and D have been drawn, then find the remaining area i.e. area exuding the circular region

AB=36 cm and M is the mid-point of AB. Semicircles are drawn on AB,AM and Mb as diametrs.A circle with centre C touches all the three circles. Find the area of the shaded region.

A cow is tied with a rope of length 7 cm at the corner of a triangular field with each side 15cm. If the length of the rope is increased by

4.5 m, find the area of the field in which the cow can graze.An elastic belt is placed round the rim of a pulley of radius 5 cm. One point on the belt is pulled directly away from the centre O of the pulley until it is at P, 10 cm from O.find the length of the belt that is in contact with the rim of the pulley.

REALLY HARD QUESTION

Q19. The given figure is made ABCDE with centre O, a small circle BQOP , two semicircles and a sector OED. AC is 28 cm. Find the total shaded area of the figure.

(1) ( 198 $\mathrm{\pi}$ – 98) cm

^{2}(2) ( 49$\mathrm{\pi}$ – 198) cm^{2}(3) ( 150$\mathrm{\pi}$ – 100) cm^{2}(4) ( 147$\mathrm{\pi}$ – 196) cm^{2}In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.

Q.1. Use the following figure to find x$\xb0$ and y$\xb0$.

(A) x = 50$\xb0$, y = 30$\xb0$

(B) x = 30$\xb0$, y = 50$\xb0$

(C) x = 50$\xb0$, y = 60$\xb0$

(D) x = 55$\xb0$, y = 65$\xb0$

two circles touch internally, the sum of their areas is 116 pie sq cm and distances between their centres is 6cm. find the radii of the circles.

plzzzzz ans!!!! its urgent!!!

the perimeter of a quadrant is 25 cm.find area of quadrant. plzzz fast..

The boundary of the shaded region in the figure given consists of four semi-circular arcs, the smallest two being equal. If the diameter of the larger is 14 cm and of the smallest is 3·5 cm, calculate the length of the boundary and the area of the shaded region. (Take = 22/7).

1] the perimeter of a quadrant of a circle of radius ' r ' is ___________.

2] Area of a quadrant of circle whose circomference is 22cm is ____________.

Given: ABCD is a square

Find : Area of the shaded region

in the fig O is the centre of circle with AC =24cm and AB=7 cm. and angle BOD =90. find the area of the shaded region..

NOT ABLE TO UPLOAD THE DIAGRAM....

its like a circle a diamete.two semicircles are thus formed.

one upper side of the diameter a triangleABC is formed with BC as its base n BC is the diameter...the on the lower side of the diameter the portion i.e the semicircle is biscetedby OD the radius...

IN the triangle AB is the smallest side AB the longest n AC the shortest...

pls make it as soon as possible tommorow is my maths exam...pls

In a circular table cover of radius 32 cm, a design is formed leaving an equilateral triangle ABC in the middle as shown in the given figure. Find the area of the design (Shaded region).

A chord of a circle of radius 12 cm subtends an angle of 120° at the centre. Find the area of the corresponding segment of the circle. please explain me in easy way?

The circumference of two circles are in the ratio 2 : 3. Find the ratio of their areas........

In figure, ABC is a right angled triangle, right angled at A. Semicircles are drawn on AB, AC and BC as diameters. Find the area of the shaded region.

Please see the figure:http://puu.sh/2e9qw

OABCO is a quadrant of a circle of diameter 14 cm.the perimeter of the quadrant is?

a wooden article was made by scooping out a hemisphere from each end of a solid cylinder.I the height of the cylinder is 10cm and it's base radius is 3.5cm. find it total s.a.

wht is the formula lr/2 where l is the lenght of arc, r is the radius ?

are there any other such formulae

Find the area of the shaded region in the given figure, where a circular arc of radius 6 cm has been drawn with vertex O of an equilateral triangle OAB of side 12 cm as centre.

M

pls explain me

(1) 13 + 5π (2) 17 + 5π (3) 7 + 10π (4) 7 + 5π

The area of a circle inscribed in an equilateral triangle is 154 cm2. Find the perimeter of the triangle.

1. New radius = r + 40/100 x r

= r(140-100)

why is 100 added to the numerator??

2. Increase in surface area = [pi (1.4r sq.) - pir sq.]/ pir sq.

why is original area not only subtracted but also divided by new area

The inner circumference of the circular track is 440 m and the track is 14 m wide.Calculate the cost of levelling the track at the rate of 25 paise per sq. m.Also, find the cost of fencing the outer circle at the of Rs. 5 per m.[Use pi = 22/7]

In an equilateral triangle of side 24cm , a circle is inscribed touching its sides . Find the area of the remaining portion of the triangle .

A Quadrilateral ABCD is drawn to circumscribe a circle. if AB=12cm,BC=15cm,CD=14cm then AD IS:

Fig shows a sector of a circle, centre O containing an angle θ.

Find the perimeter and area of the shaded region.

find i) perimeter = r (tan θ + sec θ + πθ/180 – 1)

ii)Area = r2/2(tan θ – πθ /180)

i need fully solved ..........hurry please....

is 25π cm

,then AB is equal to

(a) 5 cm (b) 8 cm (c) 10 cm (d) 25 cm

an archery target has 3 regions formed by three concentric circles. if the diameters of the concentric circles are in the ratio 1:2:3, then find the ratio of the areas of the regions???guys plz help me....

need this answer before 10:30 am today...

Find the area of a quadrant of a circle whose circumference is 22cm.

The circumference of a circle exceeds its diameter by 16.8 cm. Find the circumfrence of the circle.

all the vertices of a rhombus lie on a circle. find the area of the rhombus if the area of the circle is 1256cm

^{2}a bicycle wheel makes 5000 revolutions in moving 11km find diameter of the wheel

Q=AB is the diameter of a circle,center O .C is a point on the circumference such that /-COB=a.The area of minor segment cut off by AC is equal to twice the area of the sector BOC. Prove thatsin a/2 cos a/2 =pie(1/2- a/120)With vertices A,B and C of a triangle ABC as centres, arcs are drawn with 5cm each. With sides AB=14cm, BC=48cm and CA =50cm, find Area of whole triangle minus the sum of the three sectors

ABCD is a trapezium AB ||DC and angle BCD =60 degree.if befc is sector with center C and ab=bc=7cm and de=4 cm ,then find the area of the shaded region?

Two Concentric Circles of radii A and B ( A>B) are given. the Chord AB of larger circle touches the smaller circle at C. The length of AB is

If a, b and c are the sides of a right angle triangle where C is the hypotenuse. Prove that radius, r of the circle touches the sides of the triangle given by

r=a+b-c21. the shape of the top of a table in a restaurant is that of a sector of a circle with centre O an dang;e bod=90. if bo=od=60cm, find the area of the table and the perimeter of the table top.

2. triangle ABC is right angled at A. semicircles are drawn on AB, AC and BC as diameters. find the area of the shaded region .

3.OPQR is a rhombus , three of whose vertices lie on a circle with centre O. if the area of the rhombus is 32root3 cm sq. , find the radius of the circle.

4.O is the centre of the biggre circle an dAC is the diameter. another circle with AB as diameter is drawn. if AC=54cm and BC=10cm, find the area of the shaded region.

ABCP is a quadrant of a circle of radius 14 cm With AC as a diameter, a semicircle is drawn. Find the area of the shaded region. (Take Pi=22/7)

The figure consists of a rt. angled triangle ABC, with AC as the hypotenuse. A semicircle APC is drawn with AC as the diameter. Over this, another the arc of the quadrant extends. The shaded region is between the arc of the semicircle and the arc of the quadrant.

In the given figure, ABCD is a rectangle of dimensions 21 cm x 14 cm. A

semicircle is drawn with BC as diameter. Find the area and the

perimeter of the shaded region in the figure.

what is the formula of area of minor segment and major segment?

The area of an equilateral triangle ABC is 17320.5 cm

^{2}. With each vertex of the triangle as centre, a circle is drawn with radius equal to half the length of the side of the triangle (See the given figure). Find the area of shaded region. [Use π = 3.14 and]plz answer this question....and plz tell me step by step......can anyone...help me..

in a circle with centre o.the area of sector oAPB is 5/18 of the area find the area of x

can you give the formulae for perimeter of the minor segment in a circle?

an equilateral triangle abc of side 6 cm has been inscribed in a circle . find the area of the shaded region . thai is the remaining part of the circle

In RD Sharma Chapter 15 : Areas related to circles: Revision exercise Question 32, how is the radius of the circle with centre C ,1/6th of AB ..???

a square of side 4cm is inscribed in a circle. find the area enclosed between the circle and the square

3 circles each of radius 3.5 cm are drawn in such a way that each of them touches the other two . find the area enclosed between these three cicles (shaded region )use pie=22/7?

The difference between circumference and diameter of a circle is 135 cm. Find the radius of a circle?