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Syllabus

A particle is moving in a circle of radius R with constant speed . The time period of particle is T=1 Second in a time t = T/6 , If the difference between average speed and magnitude of average velocity of the partical is 2m/sec, find the radius of the circle(in meteres)

^{2}. If the initial velocity is u, the distance covered in 't' seconds isa) aut

b) 1/a ln(aut)

c) 1/a ln(1+aut)

d) aln(aut)

2 particles P and Q are moving with constant velocities ( i + j ) m/s and (-i + 2j) m/s respectively.At time t=0, P is at origin and Q is at a point with position vector (2i + j) m. If the equation of the trajectory of Q as observed by P is x+2y=n find n^{3}+21t^{2}+60t+6 where X is in meter And t is in second . find the acceleration of the particle when its velocity is zero ?what I have to do?

^{-1}.{Take the horizontal as the reference level for the gravitational potential energy.}

(1)

(2)

(3)

(4)

a) The velocity of the particle is constant

b) The acceleration of the particle is constant

c) The magnitude of acceleration is constant.

c) The magnitude of acceleration s decreasing continuously.

^{3/2}. If the particle starts its motion fro origin with velocity of 4m/s, the position x of the particle at an instant terms of v can be given asA particle is moving in a circle of radius

rhaving centre atOwith a constant speedv, the magnitude of change in velocity in moving fromAtoBis1)2v

2) 0

3)

v4) v

Q: The position vector of a particle in a circular motion about the origin sweeps out equal area in equal time is ?

^{}A SWIMMER SWIMS ACROSS A 2 KM WIDE RIVER BY KEEPING 150 DEGREE WITH FLOW OF RIVER. THE RIVER FLOWS WITH 2KM/H AND THE SPEED OF THE SWIMMER IN STILL WATER IS 3KM/H. FIND THE TIME HE TAKES TO CROSS THE RIVER.PLS XPLAIN IN DETAIL WITH A DIAGRAM

a person standing on the roof of a 40 m high tower, throws a ball vertically upwards with speed 10m/s. 2 seconds later, he throws another ball again in vertical downward direction(g=10m/s^2) if both hit the ground simultaneously, then choose the correct options.a) the first ball hits the ground after 4 seconds.

b) the second ball was projected vertically downwards with speed 5m/s.

c) the distance travelled by the first ball is 10 m greater than the distance travelled by the second ball.

d) both balls hit the ground with same velocities.

^{2}for 4.2s, making the straight skid marks 62.4m long ending at the tree. With what speed does the car then strike the tree?please answer as soon as possible!!

t= 0,x= +10 m. In which region particle is moving towards the origin?Options:ABandBCBCandDEBCandCDCDandDET=sqrt(2Rtantheta/g) tantheta=gT^2/2R

A hemispherical bowl of radius 10 m rotates about its vertical axis with an angular velocity 1.4 rad/s. A point particle of mass 10-2 kg placed on the smooth inner surface of the bowl, also rotates with the same speed. The particle is at a height h from the bottom of the bowl. Find the height of the particle.

^{2}-4s)/a].^{-2}. Then find the maximum distance between A and B before B overtakes Aspeed" change in a uniform circular motion ........if yes ??? i think it is scalar and change in direction wont make any change

if acceleration is varying with time we does not use kinematics equation,.we will use this equation for constant acceleration why plzexplain?